2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Electro Magnetic Induction

JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Application of EMI (Motor, Dynamo, Transformer)

  • question_answer
    In a region of uniform magnetic induction \[B={{10}^{-2}}\,tesla\], a circular coil of radius 30 cm and resistance p2 ohm is rotated about an axis which is perpendicular to the direction of B and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is                                               [CBSE PMT 1990]

    A)            4p2 mA                                   

    B)            30 mA

    C)            6 mA                                        

    D)            200 mA

    Correct Answer: C

    Solution :

                       Amplitude of the current \[{{i}_{0}}=\frac{{{e}_{0}}}{R}=\frac{\omega NBA}{R}=\frac{2\pi \nu NB(\pi {{r}^{2}})}{R}\] \[{{i}_{0}}=\frac{2\pi \times 1\times {{10}^{-2}}\times \pi {{(0.3)}^{2}}}{{{\pi }^{2}}}=6\times {{10}^{-3}}A=6mA\]


You need to login to perform this action.
You will be redirected in 3 sec spinner