JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Application of EMI (Motor, Dynamo, Transformer)

  • question_answer
    A power transformer is used to step up an alternating e.m.f. of 220 V to 11 kV to transmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary ? Assume 100% efficiency for the transformer [MP PET 1997]

    A)            4 A

    B)            0.4 A

    C)            0.04 A                                      

    D)            0.2 A

    Correct Answer: B

    Solution :

               \[{{i}_{s}}=\frac{{{P}_{s}}}{{{V}_{s}}}=\frac{4.4\times {{10}^{3}}}{11\times {{10}^{3}}}=0.4\ A\]      


You need to login to perform this action.
You will be redirected in 3 sec spinner