A) Voltage
B) Current
C) Power
D) Current density
Correct Answer: B
Solution :
We know that for step down transformer \[{{V}_{p}}>{{V}_{s}}\] but \[\frac{{{V}_{p}}}{{{V}_{s}}}=\frac{{{i}_{s}}}{{{i}_{p}}};\ \ \therefore {{i}_{s}}>{{i}_{p}}\] Current in the secondary coil is greater than the primary.
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