A) \[\frac{\sqrt{3}}{2}x+y=0\]
B) \[x+\sqrt{3}y=0\]
C) \[\sqrt{3}x+y=0\]
D) \[x+\frac{\sqrt{3}}{2}y=0\]
Correct Answer: C
Solution :
Slope of QR = \[\frac{3\sqrt{3}-0}{3-0}=\sqrt{3}\] i.e., \[\theta ={{60}^{o}}\] Clearly, \[\angle PQR={{120}^{o}}\] OQ is the angle bisector of the angle, so line OQ makes 120o with the positive direction of x-axis. Therefore equation of the bisector of \[\angle PQR\] is \[y=\tan {{120}^{o}}x\] or \[y=-\sqrt{3}x\]i.e.,\[\sqrt{3}x+y=0\].You need to login to perform this action.
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