JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Alternating Current, Voltage and Power

  • question_answer
    A lamp consumes only 50% of peak power in an a.c. circuit. What is the phase difference between the applied voltage and the circuit current                                            [MP PMT 2004]

    A)            \[\frac{\pi }{6}\]                 

    B)            \[\frac{\pi }{3}\]

    C)            \[\frac{\pi }{4}\]                 

    D)            \[\frac{\pi }{2}\]

    Correct Answer: B

    Solution :

                       \[P=\frac{1}{2}{{V}_{o}}{{i}_{o}}\cos \varphi \Rightarrow P={{P}_{Peak}}.\cos \varphi \]            \[\Rightarrow \frac{1}{2}({{P}_{peak}})={{P}_{peak}}\cos \varphi \Rightarrow \cos \varphi =\frac{1}{2}\Rightarrow \varphi =\frac{\pi }{3}\]


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