JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Alternating Current, Voltage and Power

  • question_answer
    A 280 ohm electric bulb is connected to 200V electric line. The peak value of current in the bulb will be [MP PET 2002]

    A)            About one ampere           

    B)            Zero

    C)            About two ampere           

    D)            About four ampere

    Correct Answer: A

    Solution :

               \[{{i}_{rms}}=\frac{200}{280}=\frac{5}{7}A.\] So \[{{i}_{0}}={{i}_{rms}}\times \sqrt{2}=\frac{5}{7}\times \sqrt{2}\approx 1A.\]


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