JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Alternating Current, Voltage and Power

  • question_answer
    An alternating current is given by the equation \[i={{i}_{1}}\cos \omega \,t+{{i}_{2}}\sin \omega \,t\]. The r.m.s. current is given by [MP PMT 1994]

    A)            \[\frac{1}{\sqrt{2}}({{i}_{1}}+{{i}_{2}})\]                      

    B)            \[\frac{1}{\sqrt{2}}{{({{i}_{i}}+{{i}_{2}})}^{2}}\]

    C)            \[\frac{1}{\sqrt{2}}{{(i_{1}^{2}+i_{2}^{2})}^{1/2}}\]

    D)            \[\frac{1}{2}{{(i_{1}^{2}+i_{2}^{2})}^{1/2}}\]

    Correct Answer: C

    Solution :

               \[{{i}_{rms}}=\sqrt{\frac{i_{1}^{2}+i_{2}^{2}}{2}}=\frac{1}{\sqrt{2}}{{(i_{1}^{2}+i_{2}^{2})}^{1/2}}\]


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