A) 200
B) 100
C) 50
D) 25
Correct Answer: C
Solution :
\[{{V}_{rms}}=\frac{200}{\sqrt{2}},\ \ {{i}_{rms}}=\frac{1}{\sqrt{2}}\] \[\therefore P={{V}_{rms}}\ {{i}_{rms}}\cos \varphi =\frac{200}{\sqrt{2}}\frac{1}{\sqrt{2}}\cos \frac{\pi }{3}=50\ watt\]
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