A) \[P=\frac{{{E}_{0}}{{I}_{0}}}{\sqrt{2}}\]
B) \[P=\sqrt{2}{{E}_{0}}{{I}_{0}}\]
C) \[P=\frac{{{E}_{0}}{{I}_{0}}}{2}\]
D) P = 0
Correct Answer: D
Solution :
Phase angle \[\varphi ={{90}^{o}}\], so power \[P=Vi\cos \varphi =0\]You need to login to perform this action.
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