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JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Alternating Current, Voltage and Power

  • question_answer
    The peak value of an alternating e.m.f. E is given by \[E={{E}_{0}}\cos \omega \,t\]is 10 volts and its frequency is 50 Hz. At time\[t=\frac{1}{600}sec\], the instantaneous e.m.f. is [MP PMT 1990; MP PET 2004]

    A)            10 V                                         

    B)            \[5\sqrt{3}\,V\]

    C)            5 V

    D)             1 V

    Correct Answer: B

    Solution :

                       \[E={{E}_{0}}\cos \omega t={{E}_{0}}\cos \frac{2\pi t}{T}\]            \[=10\cos \frac{2\pi \times 50\times 1}{600}=10\ \cos \frac{\pi }{6}\]\[=5\sqrt{3}\ volt.\]


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