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JEE Main & Advanced Physics Alternating Current / प्रत्यावर्ती धारा Question Bank Alternating Current, Voltage and Power

  • question_answer
    The r.m.s. value of an ac of 50 Hz is 10 amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be [MP PET 1993; KCET 2003]

    A)            2 ´ 10?2 sec and 14.14 amp

    B)            1 ´ 10?2 sec and 7.07 amp

    C)            5 ´ 10?3 sec and 7.07 amp

    D)            5 ´ 10?3 sec and 14.14 amp

    Correct Answer: D

    Solution :

                       Time taken by the current to reach the maximum value \[t=\frac{T}{4}=\frac{1}{4\nu }=\frac{1}{4\times 50}=5\times {{10}^{-3}}sec\] and \[{{i}_{o}}={{i}_{rms}}\sqrt{2}=10\sqrt{2}=14.14\]amp


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