A) \[I_{p}^{2}R\cos \theta \]
B) \[\frac{1}{2}I_{p}^{2}R\]
C) \[\frac{4}{\pi }I_{p}^{2}R\]
D) \[\frac{1}{\pi }I_{p}^{2}R\]
Correct Answer: B
Solution :
Power \[={{I}^{2}}R={{\left( \frac{{{I}_{p}}}{\sqrt{2}} \right)}^{2}}R=\frac{I_{p}^{2}R}{2}\]
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