A) 1-butene
B) 2-butene
C) 1-pentene
D) 2-pentene
Correct Answer: D
Solution :
\[C{{H}_{3}}C{{H}_{2}}CH=CHC{{H}_{3}}\underset{Zn/{{H}_{2}}O}{\mathop{\xrightarrow{{{O}_{3}}}}}\,\underset{\text{Propanal}}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,+\underset{\text{Ethanal}}{\mathop{CHOC{{H}_{3}}}}\,\]You need to login to perform this action.
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