A) \[{{C}_{2}}{{H}_{4}}\]
B) \[{{C}_{2}}{{H}_{2}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[{{C}_{6}}{{H}_{6}}\]
Correct Answer: A
Solution :
\[C{{H}_{2}}=C{{H}_{2}}\underset{(2\,)\,Zn/{{H}_{2}}O}{\mathop{\xrightarrow{(1)\,{{O}_{3}}}}}\,HCHO+HCHO\]
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