A) \[\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}}{\mathop{\underset{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}{\mathop{C{{H}_{3}}-C{{H}_{2}}-CH-Br}}\,}}\,\]
B) \[\underset{C{{H}_{3}}\,\,\,\,\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{H}_{3}}-CH-C{{H}_{2}}-Br}}\,}}\,\]
C) \[\underset{\,\,\,\,\,\,\,\,\,C{{H}_{3}}}{\mathop{\underset{\,\,\,\,|}{\mathop{\overset{\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}}{\mathop{\overset{\,\,\,\,\,\,|}{\mathop{C{{H}_{3}}-C-Br}}\,}}\,}}\,}}\,\]
D) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-Br\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{3}}+B{{r}_{2}}\underset{\,\,\,\,{{130}^{o}}C}{\mathop{\xrightarrow{\text{Light}}}}\,\]\[\underset{\begin{smallmatrix} \text{2}-\text{Bromo}\,\text{butane}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{ } \\ \,\,\,\text{(Main}\,\text{product)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{\underset{Br\,\,}{\mathop{|\,\,\,\,\,}}\,}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}}}\,+\underset{\begin{smallmatrix} \text{1}-\text{Bromo}\,\text{butane} \\ \,\,\,\,\,\,\,\,\,\,\,\text{(Minor)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-Br}}\,\] 2-Bromobutane is the main product because \[{{2}^{o}}\]carbonium ion is more stable than \[{{1}^{o}}\].
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