A) a
B) \[{{b}^{2}}-4ac\]
C) \[c+\frac{2{{b}^{2}}}{a}\]
D) \[25{{x}^{2}}+\frac{1}{4{{x}^{2}}}\]
Correct Answer: C
Solution :
(c) \[x=\frac{b}{a}\Rightarrow a\left( \frac{{{b}^{2}}}{{{a}^{2}}} \right)+b\left( \frac{b}{a} \right)+c\] \[=\frac{{{b}^{2}}}{a}+\frac{{{b}^{2}}}{a}+c=c+\frac{2{{b}^{2}}}{a}\]
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