A) \[2n-1~\]
B) \[4n+3~\]
C) \[4n+1\]
D) \[{{n}^{2}}-1\]
Correct Answer: B
Solution :
(b) These problems are solved by observations. \[{{T}_{1}}=7,{{T}_{2}}=11,{{T}_{3}}=15\Rightarrow \]Regular difference of 4. For \[n=1:\] \[{{T}_{1}}=4\times 1+3=7,\,{{T}_{2}}=4\times 2+3=11\] and so on.
You need to login to perform this action.
You will be redirected in
3 sec
