A) \[\frac{1-5q}{40q}\]
B) \[\frac{1-5q}{4q}\]
C) \[\frac{1-5pq}{4q}\]
D) \[\frac{1-5pq}{4{{p}^{2}}q}\]
Correct Answer: C
Solution :
(c) \[\frac{3\cancel{{{p}^{2}}}\left\{ 1-5pq \right\}}{12\cancel{{{p}^{2}}}q}=\frac{1-5pq}{4q}\]
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