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6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    If \[{{x}^{2}}+{{y}^{2}}+2y+4x+5=0\] then find\[\frac{x-y}{x+y}=?\]

    A)  3                                

    B)  \[-3\]

    C) \[\frac{1}{3}\]                        

    D)  \[\frac{-1}{3}\]

    Correct Answer: D

    Solution :

    \[{{x}^{2}}+4x+4+{{y}^{2}}+2y+1=0\] \[{{(x+2)}^{2}}+{{(y+1)}^{2}}=0\] \[{{(x+2)}^{2}}=0,\,\,x=-2\] \[{{(y+1)}^{2}}=0,\,\,y=-1\] Now,\[\frac{x-y}{x+y}=\frac{-2+1}{-2-1}=\frac{-1}{-3}=\frac{1}{3}\]


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