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6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    If \[a+\frac{4}{a}=4\] (Here\[a\ne 0\]) then find\[{{a}^{2}}+\frac{1}{{{a}^{3}}}=\]?

    A)  \[2\frac{1}{8}\]                                 

    B)  \[3\frac{1}{8}\]

    C)  \[4\frac{1}{8}\]                     

    D) \[5\frac{1}{8}\]

    Correct Answer: C

    Solution :

    \[a+\frac{4}{a}=4\] \[{{a}^{2}}+4=4a\] \[{{a}^{2}}-4a+4=0\] \[{{(a-2)}^{2}}=0\] \[\therefore \]\[a=2\] Now, \[{{a}^{2}}+\frac{1}{{{a}^{3}}}\] \[{{2}^{2}}+\frac{1}{{{2}^{3}}}\] \[4+\frac{1}{8}\] \[4\frac{1}{8}\]


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