6th Class Mathematics Algebra Question Bank Algebra

  • question_answer
    If \[x-\frac{1}{x}=9,\] find the value of\[a{{x}^{2}}+\frac{1}{{{x}^{2}}}=\]?

    A)  83

    B)  84

    C)  85

    D)  86

    Correct Answer: A

    Solution :

    \[x-\frac{1}{x}=9\] Squaring both side \[\Rightarrow \]\[{{\left( x-\frac{1}{x} \right)}^{2}}={{(9)}^{2}}\] \[\Rightarrow \,\,{{x}^{2}}+\frac{1}{{{x}^{2}}}-2=81\] \[\therefore \]\[{{x}^{2}}+\frac{1}{{{x}^{2}}}=81+2=83\]


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