A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
\[\frac{3}{4}\left( 7x-1 \right)-\left( 2x-\frac{1-x}{2} \right)=x+\frac{3}{2}\] \[\Rightarrow \]\[\frac{21x-3}{4}-\left\{ \frac{4x-(1-x)}{2} \right\}=x+\frac{3}{2}\] \[\Rightarrow \]\[\frac{21x-3}{4}-\frac{5x-1}{2}-x=\frac{3}{2}\] \[\frac{21x-3-2(5x-1)-4x}{4}=\frac{3}{2}\] \[21x-3-10x+2-4x=6\] \[7x-1=6\] \[\therefore \]\[x=\frac{7}{7}=1\] \[7x-1=6\]
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