question_answer

If \[{{a}^{x}}={{b}^{y}}\]and \[{{b}^{2}}=ac\], then \[\frac{1}{x}+\frac{1}{z}\]

A)  \[\frac{2}{y}\]                                    

B)  \[\frac{1}{y}\]

C)  \[\frac{1}{2}y\]               

D)         \[2y\]