A) 1/128
B) 32
C) 128
D) None of the above
Correct Answer: C
Solution :
Volume of the gas \[V=\frac{m}{d}\]and using \[P{{V}^{\gamma }}\]= constant We get \[\frac{P'}{P}={{\left( \frac{V}{V'} \right)}^{\gamma }}=\,{{\left( \frac{d'}{d} \right)}^{\gamma }}={{(32)}^{7/5}}=128\]You need to login to perform this action.
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