A) \[P'=P\]
B) \[P'=2P\]
C) \[P'=P\times {{(2)}^{15/2}}\]
D) \[P'=7P\]
Correct Answer: C
Solution :
\[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma }}\Rightarrow \frac{P'}{P}={{(8)}^{5/2}}\Rightarrow P'=P\times {{(2)}^{15/2}}\]
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