A) \[{{10}^{o}}C\]
B) \[{{887}^{o}}C\]
C) \[668K\]
D) \[{{144}^{o}}C\]
Correct Answer: C
Solution :
\[T{{V}^{\gamma -1}}=\]constant \[\Rightarrow {{T}_{2}}={{T}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}=(273+18)\ {{\left( \frac{V}{V/8} \right)}^{0.4}}=668K\]
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