JEE Main & Advanced Physics Thermodynamical Processes Question Bank Adiabatic Process

  • question_answer
    Helium at \[{{27}^{o}}C\] has a volume of 8 litres. It is suddenly compressed to a volume of 1 litre. The temperature of the gas will be \[[\gamma =5/3]\] [CBSE PMT 1993; MP PMT 1999; Pb. PMT 2002]

    A)            \[{{108}^{o}}C\]                  

    B)            \[{{9327}^{o}}C\]

    C)            \[{{1200}^{o}}C\]               

    D)            \[{{927}^{o}}C\]

    Correct Answer: D

    Solution :

               \[T{{V}^{\gamma -1}}=\]constant\[\Rightarrow {{T}_{2}}={{T}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}={{927}^{o}}C\]


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