A) \[P/2\]
B) \[P/4\]
C) \[P\]
D) 2P
Correct Answer: C
Solution :
\[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] If \[A=B=P\] and \[\theta =120{}^\circ \] then \[R=P\]You need to login to perform this action.
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