JEE Main & Advanced Physics Vectors Question Bank Addition and Subtraction of Vectors

  • question_answer
    Two equal forces (P each) act at a point inclined to each other at an angle of 120°. The magnitude of their resultant is                                                  [Karnataka CET 2004]

    A)                 \[P/2\] 

    B)                 \[P/4\]

    C)                 \[P\]     

    D)                 2P

    Correct Answer: C

    Solution :

                        \[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] If \[A=B=P\] and \[\theta =120{}^\circ \] then \[R=P\]


You need to login to perform this action.
You will be redirected in 3 sec spinner