A) \[{{H}_{3}}P{{O}_{4}}\]
B) \[{{H}_{2}}PO_{4}^{-}\]
C) \[PO_{4}^{3-}\]
D) \[{{H}_{3}}{{O}^{+}}\]
Correct Answer: A
Solution :
\[\underset{\text{Conjugate acid}}{\mathop{{{H}_{3}}P{{O}_{4}}}}\,\] ⇌ \[{{H}^{+}}+{{H}_{2}}PO_{4}^{-}\]
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