A) \[{{H}_{3}}P{{O}_{4}}\]
B) \[{{P}_{2}}{{O}_{5}}\]
C) \[PO_{4}^{3-}\]
D) \[HPO_{4}^{2-}\]
Correct Answer: D
Solution :
\[\underset{\text{Conjugate acid}}{\mathop{{{H}_{2}}PO_{4}^{-}}}\,\to {{H}^{+}}+\underset{\text{Conjugate base}}{\mathop{HPO_{4}^{2-}}}\,\]
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