A) \[C{{l}^{-}}\]
B) \[C{{H}_{3}}CO{{O}^{-}}\]
C) \[S{{O}_{4}}^{--}\]
D) \[N{{O}_{2}}^{-}\]
Correct Answer: B
Solution :
Because it is conjugate base of weak acid. \[C{{H}_{3}}COOH\]⇌ \[C{{H}_{3}}CO{{O}^{-}}+{{H}^{+}}\].
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