A) \[\frac{1}{2\pi \sqrt{3}}\]
B) \[2\pi \sqrt{3}\]
C) \[\frac{2\pi }{\sqrt{3}}\]
D) \[\frac{\sqrt{3}}{2\pi }\]
Correct Answer: C
Solution :
Velocity \[v=\omega \sqrt{{{A}^{2}}-{{x}^{2}}}\] and acceleration \[={{\omega }^{2}}x\] Now given, \[{{\omega }^{2}}x=\omega \sqrt{{{A}^{2}}-{{x}^{2}}}\]Þ \[{{\omega }^{2}}.1=\omega \sqrt{{{2}^{2}}-{{1}^{2}}}\] Þ \[\omega =\sqrt{3}\] \ \[T=\frac{2\pi }{\omega }=\frac{2\pi }{\sqrt{3}}\]
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