A) \[\frac{\pi }{2}cm/{{s}^{2}}\]
B) \[\frac{{{\pi }^{2}}}{2}cm/{{s}^{2}}\]
C) \[\frac{\pi }{4}cm/{{s}^{2}}\]
D) \[\frac{\pi }{4}cm/{{s}^{2}}\]
Correct Answer: B
Solution :
Comparing given equation with standard equation, \[y=a\sin (\omega t+\varphi ),\] we get, \[a=2\,cm,\] \[\omega =\frac{\pi }{2}\] \[\therefore {{A}_{max}}={{\omega }^{2}}A\]\[={{\left( \frac{\pi }{2} \right)}^{2}}\times 2\] \[=\frac{{{\pi }^{2}}}{2}cm/{{s}^{2}}\].
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