JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Acceleration of Simple Harmonic Motion

  • question_answer
    The displacement of an oscillating particle varies with time (in seconds) according to the equation y (cm) = sin \[\frac{\pi }{2}\left( \frac{t}{2}+\frac{1}{3} \right)\]. The maximum acceleration of the particle is approximately                                          [AMU 1995]

    A)            \[5.21cm/{{s}^{2}}\]         

    B)            \[3.62cm/{{s}^{2}}\]

    C)            \[1.81cm/s\]                        

    D)            \[0.62cm/{{s}^{2}}\]

    Correct Answer: D

    Solution :

               \[{{a}_{\max }}={{\omega }^{2}}a={{\left( \frac{\pi }{4} \right)}^{2}}a=0.62\ cm/se{{c}^{2}}\]       [\[\because \] a =1]


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