A) \[\frac{{{10}^{5}}}{2\pi }{{s}^{-1}}\]
B) \[\frac{{{10}^{6}}}{2\pi }{{s}^{-1}}\]
C) \[2\pi \times {{10}^{5}}{{s}^{-1}}\]
D) \[2\pi \times {{10}^{6}}{{s}^{-1}}\]
Correct Answer: A
Solution :
Impedance of LCR circuit will be minimum at resonant frequency so \[{{\nu }_{0}}=\frac{1}{2\pi \sqrt{LC}}\] \[=\frac{1}{2\pi \sqrt{1\times {{10}^{-3}}\times 0.1\times {{10}^{-6}}}}\] \[=\frac{{{10}^{5}}}{2\pi }Hz\]
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