A) 94
B) 14
C) 10
D) 76
Correct Answer: C
Solution :
\[{{V}_{L}}=46\,volts,\]\[{{V}_{C}}=40\,volts\], \[{{V}_{R}}=8\,volts\] E.M.F. of source \[V=\sqrt{{{8}^{2}}+{{(46-40)}^{2}}}=10\,volts\]You need to login to perform this action.
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