A) 10 mA
B) 20 mA
C) 40 mA
D) 80 mA
Correct Answer: B
Solution :
Reading of ammeter \[={{i}_{rms}}=\frac{{{V}_{rms}}}{{{X}_{C}}}=\frac{{{V}_{0}}\omega C}{\sqrt{2}}\] \[=\frac{200\sqrt{2}\times 100\times (1\times {{10}^{-6}})}{\sqrt{2}}=2\times {{10}^{-2}}A=20\ mA\]
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