A) \[{{t}_{1}}={{t}_{2}}\]
B) \[{{t}_{1}}>{{t}_{2}}\]
C) \[{{t}_{2}}>{{t}_{1}}\]
D) \[{{t}_{2}}\ge {{t}_{1}}\]
Correct Answer: B
Solution :
\[AlC{{l}_{3}}\] furnishes more ions than \[CaC{{l}_{2}}\] and thus shows higher boiling point i.e. \[{{t}_{1}}>{{t}_{2}}\].
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