Answer:
Mass
of a cracker,
Initially, cracker is at rest i.e., u = 0
Therefore, initial momentum of the cracker = mu = 0
(1)
After explosion, mass of each piece
and
Let,
velocity of first
piece
velocity of second piece
Momentum of cracker after
explosion
Applying law of conservation of momentum Total final
momentum = Total initial momentum
or
The negative sign shows that
and
are equal in magnitude and opposite
in direction.
Thus, two pieces of the cracker fly in opposite
directions with same speed.
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