molecules of carbon dioxide 
(b) the
number of molecules of 0.25 mol of
.
(c) the
formula unit mass of 
.
[Atomic mass
of Na = 23 u, S = 32 u, 0 = 16u,
]
Answer:
(a) Molar
mass of 
= 12+2 x 16 = 44 g
44 g of contains = 6.022 x 1023
molecules or the mass of 6.022 x10 molecules of
Mass of 1.0505 x 1023
molecules of
(b) 
1 mole of 
have molecules = 6.022 x1023
0.25 moles of have molecules
= 6.022 x 1023
x 0.25
=1.5055 x 1023
molecules
(c) Formula
unit mass of 
= 2 x 23 + 32
+ 3 x 16
= 46 + 32 + 48 = 126
u
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