question_answer

  A saline solution contains 40 g of common salt (NaCI) and 320 g of water. Calculate the (a) number of moles of common salt present in the solution. (b) number of molecules of water present in the solution.  

Answer:

             Weight of common salt = 40 g Weight of water = 320 g Molecular weight of common salt (NaCI) = 23 +35.5 = 58.5 g/mol Molecular weight of water =1 x 2 + 16 =18 g/mol     (a) Number of moles of common salt (b) Number of molecules of water 6.022 x 1023 = 107.05 x 1023