2. Questions Bank
  3. 9th Class
  4. Science
  5. Atoms and Molecules

9th Class Science Atoms and Molecules Question Bank 9th CBSE Science Atoms and Molecules

  • question_answer
      Compute the number of ions present in 5.85 g of sodium chloride.

    Answer:

                      5.85 g of moles or 0.1 moles of NaCI particle. Each NaCI particle is equivalent to 2 ions, i.e., one  and one Total moles of ions = 0.1 x 2 = 0.2 moles Number of ions = 0.2 x 6.022X 1023 ions


You need to login to perform this action.
You will be redirected in 3 sec spinner