? Given atomic mass of
N = 14 u, atomic mass of H=1u.
(b)
Calculate the number of particles in 31 g of
molecules. Atomic mass of P =
31u.
(c) Find the number
of moles in 87 g of
. (Atomic masses of K =
39 u, S = 32 u, 0=16 u)
Answer:
(a) Molar
mass of 
atomic mass of N+3 x
atomic mass of H
= 14 + 3 x 1=
17 g = Mass if 1 mole of
Mass of 0.5 mole of 
(b) Molar
mass of 
molecules = 4 x atomic mass
of P = 4 x 31 = 124 g
Number of
particle
Avogadro's number
(approx).
(c) Molar mass of 
atomic mass of K + atomic mass
of S + 4 x atomic mass of O = 2 x 39 + 32 + 4 x 16 = 78 + 32 + 64 = 174 g Number
of moles 
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