JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 2nd and 3rd law of thermodynamics and Entropy

  • question_answer
    A process is taking place at constant temperature and pressure. Then    [KCET 2004]

    A)                 \[\Delta H=\Delta E\]    

    B)                 \[\Delta H=T\Delta S\]

    C)                 \[\Delta H=0\]  

    D)                 \[\Delta S=0\]

    Correct Answer: B

    Solution :

               \[\Delta G=\Delta H-T\Delta S\]                    at constant temperature and pressure \[\Delta G=0\]                                 \[0=\Delta T-T\Delta S\] so \[\Delta H=T\Delta S\]


You need to login to perform this action.
You will be redirected in 3 sec spinner