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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 2nd and 3rd law of thermodynamics and Entropy

  • question_answer
    For a car not engine, the source is at \[500K\] and the sink at \[300K\]. What is efficiency of this engine [BHU 2004]

    A)                 0.2         

    B)                 0.4

    C)                 0.6         

    D)                 0.3

    Correct Answer: B

    Solution :

               Given that, \[{{T}_{1}}=500K,\,\,{{T}_{2}}=300K\]                                 By using, \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\]\[=\frac{500-300}{500}=\frac{200}{500}=0.4\].


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