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JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 2nd and 3rd law of thermodynamics and Entropy

  • question_answer
    The work done to contract a gas in a cylinder, is 462 joules. 128 joule energy is evolved in the process. What will be the internal energy change in the process    [MP PMT 2003]

    A)                 + 590 joules       

    B)                 ? 334 joules

    C)                 + 334 joules       

    D)                 ? 590 joules

    Correct Answer: C

    Solution :

           As the work is done on system, it will be positive i.e.\[W=+462\,joule,\,E=-128\,joule\](heat is evolving) From the Ist law of thermodynamics                 \[\Delta E=q+w=(-128)+(+462)=+334\,Joules.\]


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