A) \[J\,mo{{l}^{-1}}\]
B) \[JK\,mo{{l}^{-1}}\]
C) \[J\,mo{{l}^{-1}}{{K}^{-1}}\]
D) \[{{J}^{-1}}{{K}^{-1}}mo{{l}^{1}}\]
Correct Answer: C
Solution :
\[\Delta S=\frac{{{q}_{rev}}}{T}\]\[\therefore \]unit of S is \[J{{K}^{-1}}mo{{l}^{-1}}\].
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