A) \[\Delta H>T\Delta S\]
B) \[\Delta H=T\Delta S\]
C) \[\Delta H=\Delta G\]
D) \[\Delta H<T\Delta S\]
Correct Answer: B
Solution :
\[{{H}_{2}}{{O}_{(g)}}\]⇌\[{{H}_{2}}{{O}_{(l)}}\] we know \[\Delta G=\Delta H-T\Delta S\] at equilibrium \[\Delta G=0\] Therefore \[\Delta H=T\Delta S\].
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