JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank 2nd and 3rd law of thermodynamics and Entropy

  • question_answer
    The enthalpy change for the transition of liquid water to steam, \[\Delta {{H}_{vap}}=37.3\,kJ\,mo{{l}^{-1}}\] at \[373\,K\]. The entropy change for the process is             [MP PET 1994]

    A)                 \[111.9\,J\,mo{{l}^{-1}}{{K}^{-1}}\]         

    B)                 \[37.3\,J\,mo{{l}^{-1}}\,{{K}^{-1}}\]

    C)                 \[100\,J\,mo{{l}^{-1}}{{K}^{-1}}\]             

    D)                 \[74.6\,J\,mo{{l}^{-1}}{{K}^{-1}}\]

    Correct Answer: C

    Solution :

           \[\Delta {{S}_{vap}}=\frac{\Delta {{H}_{vap}}}{T}=\frac{37.3\,KJ\,mo{{l}^{-1}}}{373\,\,K}\]                                 \[=0.1\,kJ\,mo{{l}^{-1}}\,{{K}^{-1}}\]\[=100\,\,J\,mo{{l}^{-1}}\,{{K}^{-1}}\].


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