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11th Class Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank 11th CBSE Physics Work, Energy, Power & Collision

  • question_answer
    If \[\vec{A}\], \[\vec{B}\] and \[\vec{C}\] are mutually perpendicular vectors, then find the value of \[\vec{A}\].(\[\vec{B}\]+\[\vec{C}\]).

    Answer:

                    \[\vec{A}\].(\[\vec{B}\]+\[\vec{C}\]) = \[\vec{A}\].\[\vec{B}\]+ \[\vec{A}\].\[\vec{C}\] = AB cos 90° + AC cos 90° = 0


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